-4x^2+35x+9=0

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Solution for -4x^2+35x+9=0 equation:



-4x^2+35x+9=0
a = -4; b = 35; c = +9;
Δ = b2-4ac
Δ = 352-4·(-4)·9
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1369}=37$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-37}{2*-4}=\frac{-72}{-8} =+9 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+37}{2*-4}=\frac{2}{-8} =-1/4 $

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